Find the zeros of the following quadratic pol | vedclass

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(C) To find the zeros of $p(x)$,we set $p(x) = 0$.$x^{2} + x - 12 = 0$We factorize the quadratic equation by splitting the middle term:$x^{2} + 4x - 3

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$-4, 3$

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(C) To find the zeros of $p(x)$,we set $p(x) = 0$.$x^{2} + x - 12 = 0$We factorize the quadratic equation by splitting the middle term:$x^{2} + 4x - 3x - 12 = 0$$x(x + 4) - 3(x + 4) = 0$$(x + 4)(x - 3) = 0$Setting each factor to zero:$x + 4 = 0 \implies x = -4$$x - 3 = 0 \implies x = 3$Therefore,the zeros of the quadratic polynomial $p(x)$ are $-4$ and $3$.

Find the zeros of the following quadratic polynomial: $p(x) = x^{2} + x - 12$.

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